-3w^2-14w-15=0

Solution for -3w^2-14w-15=0 equation:

-3w^2-14w-15=0

a = -3; b = -14; c = -15;
Δ = b2-4ac
Δ = -142-4·(-3)·(-15)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-4}{2*-3}=\frac{10}{-6}
=-1+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+4}{2*-3}=\frac{18}{-6}
=-3
$